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refactor: 邀请码逻辑调整，支持双方填写/使用邀请码统计，并移除已被邀请状态字段

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ccnetcore
2025-11-14 23:53:29 +08:00
parent da23d17af8
commit 4bd2fc357d
5 changed files with 32 additions and 71 deletions
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16
Yi.Abp.Net8/module/ai-hub/Yi.Framework.AiHub.Application/Services/CardFlipService.cs
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@@ -51,9 +51,8 @@ public class CardFlipService : ApplicationService, ICardFlipService
// 统计本周邀请人数
var invitedCount = await _inviteCodeManager.GetWeeklyInvitationCountAsync(userId, weekStart);
// 检查用户是否已被邀请
var isInvited = await _inviteCodeManager.IsUserInvitedAsync(userId);
//当前用户是否已填写过邀请码
var isFilledInviteCode = await _inviteCodeManager.IsFilledInviteCodeAsync(userId);
var output = new CardFlipStatusOutput
{
TotalFlips = task?.TotalFlips ?? 0,
@@ -63,8 +62,8 @@ public class CardFlipService : ApplicationService, ICardFlipService
CanFlip = _cardFlipManager.CanFlipCard(task),
MyInviteCode = inviteCode?.Code,
InvitedCount = invitedCount,
IsInvited = isInvited,
FlipRecords = BuildFlipRecords(task)
FlipRecords = BuildFlipRecords(task),
IsFilledInviteCode = isFilledInviteCode
};
// 生成提示信息
@@ -87,7 +86,7 @@ public class CardFlipService : ApplicationService, ICardFlipService
// 如果中奖,发放奖励
if (result.IsWin)
{
await GrantRewardAsync(userId, result.RewardAmount, $"翻牌活动第{input.FlipNumber}次中奖");
await GrantRewardAsync(userId, result.RewardAmount, $"翻牌活动-序号{input.FlipNumber}中奖");
}
// 构建输出
@@ -147,7 +146,6 @@ public class CardFlipService : ApplicationService, ICardFlipService
{
MyInviteCode = inviteCode?.Code,
InvitedCount = invitedCount,
IsInvited = inviteCode?.IsUserInvited ?? false,
InvitationHistory = invitationHistory.Select(x => new InvitationHistoryItem
{
InvitedUserName = x.InvitedUserName,
@@ -237,10 +235,10 @@ public class CardFlipService : ApplicationService, ICardFlipService
{
if (status.TotalFlips >= 7)
{
return $"本周使用他人邀请码可解锁{status.RemainingInviteFlips}次翻牌,且必中大奖!每次中奖最大额度将翻倍!";
return $"本周使用他人邀请码或他人使用你的邀请码，可解锁{status.RemainingInviteFlips}次翻牌，且必中大奖!每次中奖最大额度将翻倍!";
}
return $"本周使用他人邀请码可解锁{status.RemainingInviteFlips}次翻牌,必中大奖!每次中奖最大额度将翻倍!";
return $"本周使用他人邀请码或他人使用你的邀请码，可解锁{status.RemainingInviteFlips}次翻牌，必中大奖!每次中奖最大额度将翻倍!";
}
return "继续加油!";