feat: 增加基于本周填写邀请码数量的邀请翻牌校验

- 注入 ISqlSugarRepository<InvitationRecordAggregateRoot> 到 CardFlipManager 并更新构造函数。
- 在邀请类型（FlipType.Invite）翻牌时，改为校验用户本周已填写的邀请码数量是否满足本次翻牌所需（根据 InviteFlipsUsed 计算所需数量），不足则抛出友好异常提示。
- 保持原有错误处理与日志逻辑不变。

Yi.Abp.Net8/module/ai-hub/Yi.Framework.AiHub.Domain/Managers/CardFlipManager.cs

@@ -11,6 +11,7 @@ namespace Yi.Framework.AiHub.Domain.Managers;
 public class CardFlipManager : DomainService
 {
     private readonly ISqlSugarRepository<CardFlipTaskAggregateRoot> _cardFlipTaskRepository;
+    private readonly ISqlSugarRepository<InvitationRecordAggregateRoot> _invitationRecordRepository;
     private readonly InviteCodeManager _inviteCodeManager;
     private readonly ILogger<CardFlipManager> _logger;
 
@@ -32,10 +33,12 @@ public class CardFlipManager : DomainService
 
     public CardFlipManager(
         ISqlSugarRepository<CardFlipTaskAggregateRoot> cardFlipTaskRepository,
+        ISqlSugarRepository<InvitationRecordAggregateRoot> invitationRecordRepository,
         InviteCodeManager inviteCodeManager,
         ILogger<CardFlipManager> logger)
     {
         _cardFlipTaskRepository = cardFlipTaskRepository;
+        _invitationRecordRepository = invitationRecordRepository;
         _inviteCodeManager = inviteCodeManager;
         _logger = logger;
     }
@@ -109,13 +112,23 @@ public class CardFlipManager : DomainService
             throw new UserFriendlyException(GetFlipTypeErrorMessage(flipType));
         }
 
-        // 如果是邀请类型翻牌，必须验证用户已使用过邀请码
+        // 如果是邀请类型翻牌，必须验证用户本周填写的邀请码数量足够
         if (flipType == FlipType.Invite)
         {
-            var isInvited = await _inviteCodeManager.IsUserInvitedAsync(userId);
-            if (!isInvited)
+            // 查询本周已使用的邀请码数量
+            var weeklyInviteCodeUsedCount = await _invitationRecordRepository._DbQueryable
+                .Where(x => x.InvitedUserId == userId)
+                .Where(x => x.InvitationTime >= weekStart)
+                .CountAsync();
+
+            // 本周填写的邀请码数量必须 >= 即将使用的邀请翻牌次数
+            // 例如: 要翻第8次(InviteFlipsUsed=0->1), 需要至少填写了1个邀请码
+            //      要翻第9次(InviteFlipsUsed=1->2), 需要至少填写了2个邀请码
+            //      要翻第10次(InviteFlipsUsed=2->3), 需要至少填写了3个邀请码
+            var requiredInviteCodeCount = task.InviteFlipsUsed + 1;
+            if (weeklyInviteCodeUsedCount < requiredInviteCodeCount)
             {
-                throw new UserFriendlyException("需要使用他人邀请码才能解锁更多翻牌次数");
+                throw new UserFriendlyException($"需要先使用{requiredInviteCodeCount}个他人邀请码才能解锁第{task.TotalFlips + 1}次翻牌");
             }
         }